MHT CET Physics question
A galvanometer of resistance 99 requires 5 mA current for full scale deflection. It can be converted into an ammeter of range 0.5 A by connection a shunt resistance of
Answer: (B)
Solution
\dfrac{I_gG}{I-I_g}\dfrac{5×10^{-3}×99}{0.5-0.005}\dfrac{0.495}{0.495}$=1\
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