CH_3 - CH = CH_2 [+H_2O] Conc.H_2SO_4 P PCl_3 Q [KOH] alcoholic R . The compound R is :

MHT CET Chemistry question

\mathrm{CH_3{-}CH = CH_2 \xrightarrow[+H_2O]{Conc.H_2SO_4} P \xrightarrow{PCl_3} Q \xrightarrow[KOH]{alcoholic} R}. The compound R is :

Answer: (B)

Hydration of propene gives 2-propanol (P), gives 2-chloropropane (Q), and alcoholic KOH eliminates HCl

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Question ID VK-079040