In the reaction: CH_3CH(Br)CH_3 [KOH] alc A [peroxide] HBr B CH_3ONa C , C is :

MHT CET Chemistry question

In the reaction: \mathrm{CH_3CH(Br)CH_3 \xrightarrow[KOH]{alc} A \xrightarrow[peroxide]{HBr} B \xrightarrow{CH_3ONa} C}, C is :

Answer: (B)

Alc. KOH gives propene (A); HBr with peroxide adds anti-Markovnikov to give 1-bromopropane (B); CH3ONa then gives CH3OCH2CH2CH3

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Question ID VK-079286