CH_ 2 =CH-(CH_ 2 )_ 5 COOH [ HBr ] Peroxide Z where Z is __________

MHT CET Chemistry question

\mathrm{CH_{2}=CH-(CH_{2})_{5}COOH} Z where Z is

Answer: (B)

In the presence of peroxide, HBr adds to the terminal alkene by the free-radical (anti-Markovnikov) route, placing Br on the terminal carbon to give

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Question ID VK-080896