MHT CET Chemistry question

Right order of acidic strength is

(A)\mathrm{CH_{2}ClCOOH\ >\ HCOOH\ >\ C_{2}H_{5}COOH\ >\ CH_{3}COOH}
(B)\mathrm{CH_{2}ClCOOH\ >\ HCOOH\ >\ CH_{3}COOH\ >\ C_{2}H_{5}COOH}Correct
(C)\mathrm{C_{2}H_{5}COOH\ >\ CH_{3}COOH\ >\ HCOOH\ >\ CH_{2}ClCOOH}
(D)\mathrm{HCOOH\ >\ CH_{2}ClCOOH\ >\ CH_{3}COOH\ >\ C_{2}H_{5}COOH}

Answer: (B)

Solution

The -Cl substituent increases acidity most (pKa 2.86), formic acid has no electron-donating alkyl group (3.75), and alkyl groups decrease acidity further as their number increases (

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Question ID VK-080930