MHT CET Chemistry question

ChemistryOrganic Oxidation & Reduction ReactionsMHT CET

An alcohol (A) with molecular formula on oxidation forms compound (B) . The compound (B) gives iodoform test, but does not reduce ammoniacal silver nitrate, (B) on treatment with amalgamated zinc and HCl gives compound (C) . Identify A, B, C.

Answer: (B)

Solution

B is a methyl ketone (iodoform positive, Tollens negative), so B is butanone and A is butan-2-ol; Clemmensen reduction of butanone gives n-butane. Option (a) has an aldehyde

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Question ID VK-080952