MHT CET Chemistry question
An alcohol (A) with molecular formula on oxidation forms compound (B) . The compound (B) gives iodoform test, but does not reduce ammoniacal silver nitrate, (B) on treatment with amalgamated zinc and HCl gives compound (C) . Identify A, B, C.
Answer: (B)
Solution
B is a methyl ketone (iodoform positive, Tollens negative), so B is butanone and A is butan-2-ol; Clemmensen reduction of butanone gives n-butane. Option (a) has an aldehyde
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