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MHT CET Chemistry question

ChemistryAldehydes, Ketones and Carboxylic AcidsMHT CET

Compound (A) forms a phenyl hydrazone and gives negative Tollen's and iodo-form tests. Compound (A) on reduction gives n-pentane. Compound (A) is

Answer: (C)

Solution

A phenylhydrazone shows a carbonyl compound, negative Tollen's test rules out pentanal, negative iodoform rules out pentan-2-one (has

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Question ID VK-081105