MHT CET Physics question
A solenoid 3 m long is made by winding 2000 loops of wire on an iron rod whose cross-section is 1.5 cm. If the relative permeability of the iron is 6000. What is the self-inductance of the solenoid?
Answer: (A)
Solution
\dfrac{μ_rμ_0N^2A}{l}\dfrac{6000×4π×10^{-7}×(2000)^2×1.5×10^{-4}}${3
See the full step-by-step solution
Create a free account to read the complete working, and practise questions like this in a timed test.
Create a free account