Test SeriesFree PYQsExamsPricing

MHT CET Chemistry question

ChemistryOrganic Chemistry - Some Basic Principles and TechniquesMHT CET

The number of chiral carbon atom present in a glucose molecule is

Answer: (C)

Solution

Open-chain glucose, CHO–(CHOH)–CHOH, has four asymmetric carbons (C-2 to C-5);

See the full step-by-step solution

Create a free account to read the complete working, and practise questions like this in a timed test.

Create a free account

Question ID VK-083271