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MHT CET Physics question

PhysicsElectrostatic Potential and CapacitanceMHT CET

An electron is accelerated under a potential difference of 182 V. The maximum velocity of electron will be (Take, charge of an electron is C and its mass is kg)

Answer: (C)

Solution

gives \sqrt{\dfrac{2×1.6×10^{-19}×182}{9.1×10^{-31}}}\sqrt{6.4×10^{13}}$ =

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Question ID VK-083666