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MHT CET Physics question

PhysicsDual Nature of Matter and RadiationMHT CET

If of electron is and stopping potential is 0.71 V, then the maximum velocity of the photoelectron is

Answer: (C)

Solution

gives \sqrt{2V_0 (e/m)}\sqrt{2×0.71×1.76×10^{11}}$ ≈

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Question ID VK-083672