MHT CET Physics question
When photon of energy 4.25 eV strike the surface of a metal A, the ejected photoelectrons have maximum kinetic energy eV and de-Broglie wavelength . The maximum kinetic energy of photoelectrons liberated from another metal B by photon of energy 4.70 eV is eV. If the de-Broglie wavelength of these photoelectron is , then
Answer: (D)
Solution
, so giving eV and
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