MHT CET Physics question
A radioactive material decays by simultaneous emission of two particles with half-lives 1620 yr and 810 yr, respectively. The time (in yr) after which one-fourth of the material remains is
Answer: (D)
Solution
Decay constants add: , so yr; one-fourth remains after two such half-lives, $t = 2 × 540 =
See the full step-by-step solution
Create a free account to read the complete working, and practise questions like this in a timed test.
Create a free account