MHT CET Physics question
Not in JEE Advanced syllabus
The number densities of electrons and holes in a pure germanium at room temperature are equal and its value is per . On doping with aluminium the hole density increases to per , then the electron density in doped germanium is
Answer: (A)
Solution
By the law of mass action , so $ = (2×/(3.5× = 1.14×\ \mathrm{}
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