NEET 2002 Biology question

A diseased man marries a normal woman. They get three daughter and five sons. All the daughter were diseased and sons were normal. The gene of this disease is : -

(1)Sex linked dominantCorrect
(2)Sex linked recessive
(3)Sex limited character
(4)Autosomal dominant

Answer: (1)

Solution

A father always passes his X chromosome to all his daughters and his Y chromosome to all his sons. Here all daughters (who received the father's X) are diseased and all sons (who received his Y, and their X from the normal mother) are normal. This criss-cross pattern means the gene is on the X chromosome and expresses

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Question ID VK-089121