NEET 2003 Chemistry question
The densities of graphite and diamond at 298 K are 2.25 and 3.51 g cm, respectively. If the standard free energy difference () is equal to 1895 J mol, the pressure at which graphite will be transformed into diamond at 298 K is -
Answer: (1)
Solution
For graphite diamond, J mol at 1 bar. The free energy change at pressure is , and the two forms are in equilibrium (transformation just begins) when , i.e. . Molar volumes (12 g
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