NEET 2003 Chemistry question

ChemistryThermodynamicsNEET 2003

The densities of graphite and diamond at 298 K are 2.25 and 3.51 g cm, respectively. If the standard free energy difference () is equal to 1895 J mol, the pressure at which graphite will be transformed into diamond at 298 K is -

Answer: (1)

Solution

For graphite diamond, J mol at 1 bar. The free energy change at pressure is , and the two forms are in equilibrium (transformation just begins) when , i.e. . Molar volumes (12 g

See the full step-by-step solution

Create a free account to read the complete working, and practise questions like this in a timed test.

Create a free account

Question ID VK-089193