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NEET 2003 Biology question

BiologyPrinciples of Inheritance and VariationNEET 2003

The linkage map of X-chromosome of fruitfly has 66 units, with yellow body gene (y) at one end and bobbed hair (b) gene at the other end. The recombination frequency between these two genes (y and b) should be : -

Answer: (3)

Solution

Map distance is measured in map units (1 map unit = 1% recombination for short distances), but the observed recombination frequency between any two genes can never exceed 50%, because of multiple (double) crossovers and because only half of the

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Question ID VK-089271