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NEET 2008 Physics question

PhysicsElectromagnetic InductionNEET 2008

A long solenoid has 500 turns. When a current of 2 ampere is passed through it, the resulting magnetic flux linked with each turn of the solenoid is Wb. The self-inductance of the solenoid is

Answer: (4)

Solution

Total flux linkage , where is the self-inductance. \frac{Nφ}{i}\frac{500 × 4× 10^{-3}}{2}$ =

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Question ID VK-089972