NEET 2008 Chemistry question

The correct order of decreasing second ionisation enthalpy of Ti (22), V (23), Cr (24) and Mn (25) is

(1)Ti > V > Cr > Mn
(2)Cr > Mn > V > TiCorrect
(3)V > Mn > Cr > Ti
(4)Mn > Cr > Ti > V

Answer: (2)

Solution

Second ionisation enthalpy involves removing an electron from the monopositive ion. Configurations of : , , (half-filled, very stable), . Cr has the highest second ionisation enthalpy because its half-filled

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Question ID VK-090005