NEET 2009 Physics question
In the nuclear decay given below:
{}^{A}_{Z}X Y B^{*} B
the particles emitted in the sequence are:
Answer: (4)
Solution
Step 1: X to Y: mass number unchanged (A), atomic number rises from Z to Z+1, so a neutron changed into a proton, i.e. a beta particle (, an electron) is emitted. Step 2: Y to B*: mass number falls by 4 (A to A-4) and atomic number falls by 2 (Z+1 to Z-1), so an alpha particle
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