NEET 2010 Chemistry question

Consider the following relations for emf of an electrochemical cell : (i) EMF of cell = (Oxidation potential of anode) (Reduction potential of cathode) (ii) EMF of cell = (Oxidation potential of anode) (Reduction potential of cathode) (iii) EMF of cell = (Reduction potential of anode) (Reduction potential of cathode) (iv) EMF of cell = (Oxidation potential of anode) (Oxidation potential of cathode) Which of the above relations are correct

• (1)(iii) and (i)
• (2)(i) and (ii)
• (3)(iii) and (iv)
• (4)(ii) and (iv)Correct