NEET 2010 Physics question
A cylindrical metallic rod in thermal contact with two reservoirs of heat at its two ends conducts an amount of heat in time . The metallic rod is melted and the material is formed into a rod of half the radius of the original rod. What is the amount of heat conducted by the new rod, when placed in thermal contact with the two reservoirs in time ?
Answer: (2)
Solution
Heat conducted in time : . New radius , so new area . Volume is conserved: , so . \dfrac{K(A/4)(T_1-T_2)t}{4L}$ =
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