NEET 2010 Physics question
Not in JEE Advanced syllabus
A vibration magnetometer placed in magnetic meridian has a small bar magnet. The magnet executes oscillations with a time period of in earth's horizontal magnetic field of microtesla. When a horizontal field of microtesla is produced opposite to the earth's field by placing a current carrying wire, the new time period of magnet will be
Answer: (4)
Solution
Time period of a bar magnet oscillating in a field : , so . The new horizontal field is (opposite fields subtract). $ =
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