NEET 2011 Physics question
Two particle are oscillating along two close parallel straight lines side by side, with the same frequency and amplitudes. They pass each other, moving in opposite directions when their displacement is half of the amplitude. The mean positions of the two particles lie on a straight line perpendicular to the paths of the two particles. The phase difference is :
Answer: (2)
Solution
Take the displacement . At : , so the phase is for the particle moving towards the positive extreme (velocity positive, ), and for the particle moving the opposite way (velocity negative, $ <
See the full step-by-step solution
Create a free account to read the complete working, and practise questions like this in a timed test.
Create a free account