NEET 2016 Physics question
If the velocity of a particle is , where and are constants, then the distance travelled by it between 1 s and 2 s is:
Answer: (3)
Solution
Distance = \int_1^2 v\,dt = \int_1^2 (At + Bt^2)\,dt = \left[\dfrac{At^2}{2} + \dfrac{Bt^3}{3}\right]_1^2. \dfrac{8B}{3}\dfrac{A}{2}$ +
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