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NEET 2017 Physics question

PhysicsOscillationsNEET 2017

A particle executes linear simple harmonic motion with an amplitude of 3 cm. When the particle is at 2 cm from the mean position, the magnitude of its velocity is equal to that of its acceleration. Then its time period in seconds is

Answer: (3)

Solution

In SHM, and (in magnitude). Given at : \sqrt{3^2-2^2}\sqrt{5}$ = 2ω

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Question ID VK-092029