The limiting molar conductivities ( _0) for NaCl, KBr and KCl are 126, 152 and 150 S cm^2mol^ -1 respectively. What is the _0 of NaBR?

MHT CET 2024 Chemistry question

The limiting molar conductivities () for NaCl, KBr and KCl are 126, 152 and 150 S cmmol respectively. What is the of NaBR?

Answer: (A)

By Kohlrausch's law of independent migration of ions, . Now $(NaCl) + (KBr) - (KCl) = (λ_{}+λ_{}) + (λ_{}+λ_{}) -

Create a free account to read the complete working, and practise questions like this in a timed test.

Question ID VK-092932