MHT CET 2024 Physics question
A small sphere oscillates simple harmonically in a watch glass whose radius of curvature is 1.6 m. The period of oscillation of the sphere in second is (acceleration due to gravity, )
Answer: (A)
Solution
A small sphere rolling or sliding in a spherical bowl of radius of curvature behaves like a simple pendulum of length (the restoring component of gravity is ). So \sqrt{\dfrac{R}{g}}$ =
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