MHT CET 2024 Physics question

PhysicsWave OpticsMHT CET 2024

In an interference experiment, the bright fringe for the light of wavelength (n=0, 1, 2, 3...) coincides with the dark fringe for light of wavelength (m=1, 2, 3...). The ratio is

Answer: (C)

Solution

In Young's experiment the position of the bright fringe is () and that of the dark fringe is (). For coincidence : $nλ_1 =

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Question ID VK-093022