MHT CET 2024 Mathematics question
A random variable X has the following probability distribution. Then value of k is and has the value . X = x : 0, 1, 2, 3, 4, 5, 6, 7, 8 p(x) : k, 2k, 3k, 4k, 4k, 3k, 2k, k, k
Answer: (C)
Solution
The probabilities of a distribution add up to 1: , so . Next . Hence option (C). Options
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