MHT CET 2024 Physics question
A sphere is temperature 600K. In an external environment of 200 K, its cooling rate is 'R'. When the temperature of the sphere falls to 400 K, then cooling rate 'R' will become
Answer: (A)
Solution
For a sphere cooling by radiation in surroundings at , the rate of cooling is proportional to (Stefan-Boltzmann law). Initially K: . Later K: $ - = - 1) =
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