For a stationary wave, Y = 10 ( x 15 ) (48 t) cm, the distance between a node and the successive antinode is

MHT CET 2022 Physics question

For a stationary wave, cm, the distance between a node and the successive antinode is

Answer: (A)

Compare with : , hence . Adjacent nodes are cm apart, and a node and the next antinode are

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Question ID VK-093910