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MHT CET 2022 Physics question

PhysicsWave OpticsMHT CET 2022

In biprism experiment, the light of wavelength is used to obtain an interference pattern. Then fringe width is W at distance D from the screen. When the screen is moved towards biprism, fringe width becomes W at distance D. The distance between two virtual images of the slit is

Answer: (D)

Solution

Fringe width in a biprism experiment is , where is the separation between the two virtual images of the slit and is the distance of the screen from the (virtual) slits. Then and . Subtracting, $ - = Missing argument for \dfrac\dfrac{λ

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Question ID VK-094248