MHT CET 2022 Chemistry question

What is the number of primary and secondary alcoholic groups respectively present in glucose?

(A)2, 3
(B)3, 2
(C)4, 2
(D)1, 4Correct

Answer: (D)

Solution

Open-chain glucose is with five -OH groups. The -OH on C-6 is on a group, hence a primary alcoholic group (1). The -OH groups on C-2, C-3, C-4 and C-5 are on

See the full step-by-step solution

Create a free account to read the complete working, and practise questions like this in a timed test.

Create a free account

Question ID VK-094302