MHT CET 2024 Physics question
In S.H.M. the displacement of a particle at an instant is Y = A cos 30 where A = 40 cm and kinetic energy is 200 J. if force constant is , then x will be ()
Answer: (A)
Solution
The displacement is , so . In S.H.M. the kinetic energy is . Hence \dfrac{8 KE}{A^2}\dfrac{8×200}{(0.4)^2}\dfrac{1600}{0.16}$ =
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