MHT CET 2024 Chemistry question
What is the conductivity of 0.05 M KCl solution if cell constant is 1.32 cm and resistance is 528 ohm?
Answer: (3)
Solution
Conductivity is . Substituting, \dfrac{1.32\ cm^{-1}}{528\ Ω}10^{-3}$\ Ω^{-1}cm^{-1} =
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