Calculate freezing point of 0.05 molal aqueous solution of a non electrolyte? ( K_f = 1.86 K kg mol^ -1 , freezing point of water = 0^ C)

MHT CET 2022 Chemistry question

Calculate freezing point of 0.05 molal aqueous solution of a non electrolyte? ( = 1.86 K kg mol, freezing point of water = C)

(A)186 K
(B)272.9 KCorrect
(C)93 K
(D)279 K

Answer: (B)

Solution

For a non-electrolyte , so the depression in freezing point is K. The freezing point of water is K, so the solution freezes at $ = 273 - 0.093 = 272.907 ≈

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Question ID VK-095906