MHT CET 2026 Physics question
The moment of inertia of a ring about an axis passing through its centre and perpendicular to its plane is I. It is rotating with angular velocity . Another identical ring is gently placed on it so that their centres coincide. If both rings are rotating about the same axis then loss in kinetic energy is
Answer: (C)
Solution
No external torque acts, so angular momentum is conserved: , giving . Initial kinetic energy . Final kinetic energy $ = (2I)( =
See the full step-by-step solution
Create a free account to read the complete working, and practise questions like this in a timed test.
Create a free account