In an AC circuit E = 50 sin(500 t), I = 600sin(500t+ 3 )mA. What is the power dissipated in the circuit? [cos 60^0 = 0.5]

MHT CET 2026 Physics question

In an AC circuit E = 50 sin(500 t), I = 600sin(500t+)mA. What is the power dissipated in the circuit? [cos 60 = 0.5]

Answer: (C)

The average power in an AC circuit is , where is the phase difference between voltage and current. Here V, mA A and . So W,

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Question ID VK-096195