MHT CET 2026 Chemistry question
Calculate the enthalpy change for the following reaction, using given bond energy (kJ/mol) (C-H = 414, H-O = 463, H-Cl = 431, C-Cl = 326 and C-O = 335) CH_3OH_{(g)} + HCl_{(g)} \rightarrow CH_3Cl_{(g)} + H_2O_{(g)}
Answer: (A)
Solution
. Bonds broken: one C-O (335) and one O-H (463) in , and one H-Cl (431): kJ. Bonds formed: one C-Cl (326) in and two O-H (2 × 463 =
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