Let A(2, 3, 0), B(0,3,2) and C(4,0,3) be vertices of a triangle then the area of the triangle is
(A) sq. units
(B) sq. unitsCorrect
(C) sq. units
(D) sq. units
Answer: (B)
Solution
Area . and . Cross product: $Missing argument for \hat\hat i (0·3-2·(-3))-Missing argument for \hat\hat j ((-2)·3-2·2)+Missing argument for \hat\hat k ((-2)(-3)-0·2)=6Missing argument for \hat\hat i+10Missing argument for \hat\hat
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