MHT CET 2023 Chemistry question
Not in JEE Main or NEET syllabus
Find the radius of an atom in fcc unit cell having edge length 405 pm
Answer: (C)
Solution
In a face-centred cubic unit cell the atoms touch along the face diagonal, which equals . By Pythagoras the face diagonal is , so and \dfrac{\sqrt2 a}{4}\dfrac{a}{2\sqrt2}\dfrac{405}{2.828}$
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