MHT CET 2024 Mathematics question

MathematicsProbabilityMHT CET 2024

A random variable X has the following probability distribution X=x : 1, 2, 3, 4, 5, 6, 7, 8 P(X=x): 0.15, 0.23, 0.10, 0.12, 0.20, 0.08, 0.07, 0.05 For the event E = {X is a prime number}, F = {X < 4}, then P (E F) is

Answer: (D)

Solution

Prime values of X: 2, 3, 5, 7, so and . and . with . Hence . Directly, and

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Question ID VK-096706