MHT CET 2023 Chemistry question
Calculate the time required in second to deposit 6.35 g copper from it's salt solution by passing 5 ampere current [molar mass of Cu = 63.5 g mol]
Answer: (C)
Solution
Copper(II) is reduced as , so 1 mol Cu (63.5 g) needs 2 F. Moles of Cu mol, so charge required $Q = 0.1 × 2 × 96500 =
See the full step-by-step solution
Create a free account to read the complete working, and practise questions like this in a timed test.
Create a free account