MHT CET 2024 Chemistry question
Calculate Henry's law constant if solubility of gas in water at is and partial pressure of the gas 0.75 bar above solution.
Answer: (A)
Solution
Henry's law in terms of solubility: , so K_H = \dfrac{S}{p} = \dfrac{5.14\times10^{-4}\,mol\,dm^{-3}}{0.75\,bar} = 6.85\times10^{-4}\,mol\,dm^{-3}bar^{-1}. Hence option (A). Option (B)
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