MHT CET 2026 Chemistry question
The solubility of AgCl in 0.1 M NaCl is S mol/L. If the solubility product of AgCl is , then S is approximately:
Answer: (A)
Solution
NaCl supplies the common ion at 0.1 M. If AgCl dissolves to S mol/L, and (as S is very small). $ = [\mathrm{}][\mathrm{}]
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