MHT CET 2024 Physics question
Optical path of a particular ray of light has travelled a distance 3 cm in flint glass is same as that on travelling a distance 'x' cm through another medium. The value of 'x' is [refractive index of flint glass = 1.6, refractive index of another medium = 1.25]
Answer: (A)
Solution
Optical path = refractive index geometric distance. Equating the two optical paths: , so . Then \dfrac{4.8}{1.25}$ =
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