MHT CET 2024 Mathematics question
If a random variable X has the following probability distribution values X : 0, 1, 2, 3, 4, 5, 6, 7 P(X) : 0, k, 2k, 2k, 3k, K, 2k, 7k+k Then has the value
Answer: (A)
Solution
The probabilities must add up to 1: , i.e. . Probability cannot be negative, so . Now
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