For the reaction 2 NOBr_ (g) 2 NO_ (g) + Br_ 2(g) rate law is r=k[ NOBr ]^2, if rate constant is 1.62 mol...

Question

For the reaction 2 NOBr_ (g) 2 NO_ (g) + Br_ 2(g) rate law is r=k[ NOBr ]^2, if rate constant is 1.62 mol ,dm^ -3 s^ -1 and concentration of NOBr is 2 10^ -3 mol ,L^ -1 . What is the rate of reaction ?

Accepted Answer

(B)

MHT CET 2026 Chemistry question

Solution

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