MHT CET 2026 Physics question
A kathak dancer is standing on horizontal surface with folded hands. In the begining dancer is rotating about his central axis and his kinetic energy is 'K' at that time. The kathak dancer now stretches his arms so that the moment of inertia of the dancer becomes three times and the angular velocity becomes one-third. The kinetic energy of the dancer now is
Answer: (B)
Solution
Initially . Finally the moment of inertia is and the angular velocity is (consistent with conservation of angular momentum, ). New kinetic energy \dfrac{1}{2}$I'ω'^2 =
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